How to Calculate the Gearbox Torque
Output torque decides whether a reducer survives the duty or strips its first gear. This guide is written for design and maintenance engineers who need a usable number, not a catalog guess. You will work from motor power, ratio, speed and load, then check the service factor before you order.

In this article
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Key takeaways
What torque actually means inside a gearbox
Torque is a turning force, measured as force times lever arm. A 10 N force on a 0.1 m arm gives 1 N·m. Inside a reducer, the input shaft turns fast with low torque, and the output shaft turns slow with high torque. The gear ratio multiplies torque and divides speed. Energy is conserved, minus friction losses, so you can never get more power out than you put in.
For a first estimate, output torque equals input torque multiplied by the gear ratio and by the efficiency of the gear train. A single-stage helical pair runs at 0.96 to 0.98. A worm gearbox drops to 0.50 to 0.85 depending on the lead angle, because sliding friction is high. Planetary stages sit around 0.94 to 0.97 each. If you stack three planetary stages, multiply the three stage efficiencies together.
Engineers often ask about torque in N·m when the motor data sheet gives kW. The bridge is rotational power. Power in watts equals torque in N·m times angular speed in rad/s. In practical units, T (N·m) = 9550 × P (kW) / n (rpm). So a 2.2 kW motor at 1,450 rpm carries about 14.5 N·m at the shaft. That number is your input torque before anything else.
Gather the load data before you touch a formula
Most bad gearbox sizing starts with missing load data, not bad math. You need the driven mass, the radius or lead at which the force acts, the friction coefficient, and the acceleration time. For a conveyor, the pull force at the drum is the belt tension difference. For a ball screw, thrust force times lead divided by 2π gives the torque at the screw. For a rotating table, torque is inertia times angular acceleration.
Inertia matters more than people expect. The torque needed to accelerate a load is J × α, where J is the reflected inertia in kg·m² and α is angular acceleration in rad/s². Reflected inertia rises with the square of the ratio, so a high ratio can make a small load feel enormous at the motor. Keep the load-to-motor inertia ratio under 10:1 for servo systems, and under 5:1 when you need tight positioning.
Friction torque is easier to miss because it hides in bearings, seals and guideways. A rough rule for a ball screw axis is that preload and seal drag add 10 to 30 percent to the running torque. On a worm gearbox, self-locking means the load cannot drive the input backward, but it also means you pay for that safety in efficiency.
Write everything in one unit system before you start. We use N·m, kg, m and rad/s internally. Converting at the end, after you have already mixed kg and lb, is where errors survive into the purchase order. If a customer sends a drawing with a torque callout in lb·in, convert first: 1 lb·in = 0.113 N·m.
Core formulas for calculate the gearbox torque
Three formulas cover most sizing work. First, torque from power and speed: T (N·m) = 9550 × P (kW) / n (rpm). This gives the torque at any shaft where you know power and rotational speed. Second, torque through a ratio: T_out = T_in × i × η, where i is the numerical ratio (input speed divided by output speed) and η is the overall efficiency. Third, acceleration torque: T_acc = J × α, added to the steady-state torque to get the peak demand.
When you calculate the gearbox torque for a catalog selection, work backwards from the load. Find the torque required at the machine shaft, divide by the gearbox ratio and efficiency, and that is the required motor torque with margin. Then compare that required motor torque against the motor's rated and peak torque. If the number is larger than peak, the axis will stall and the drive will fault on overload.
Always separate continuous torque from peak torque. Continuous torque sets the thermal rating and the gearbox life. Peak torque sets the gear tooth bending stress and can cause a one-time failure. A gearbox can survive a peak for a few seconds per cycle, but not for minutes. Check the catalog for both values, and check the number of starts per hour the manufacturer allows.
Why the housing and shafts decide the real limit
A gearbox rating on paper assumes the housing holds the bearing centers in line. In a machined aluminum or cast iron housing, bore position tolerance and bore roundness set how the gears mesh. If the center distance drifts, the contact pattern moves to the tooth tip and bending stress rises quickly. That is why we hold bearing bores to ±0.005 mm on our 5-axis and mill-turn centers, then verify with a CMM report.
Output shafts carry both torque and side load. A 344 N·m output through a Ø25 mm shaft is comfortable, but a 100 mm overhung sprocket adds a bending moment that the bearing, not the shaft, must absorb. Check the catalog's permitted radial load at the actual distance from the shoulder. If the load point is farther out than the catalog point, derate the permitted value.
Material choice matters less than people assume for the housing, but a lot for the gears. Through-hardened 4140 or 4340 gears handle moderate loads. Case-hardened 20MnCr5 or 17-4PH gets a hard skin with a tough core, which resists pitting and bending together. For prototypes and low-volume reducers, machined gears in 7075 or 4140 are practical, because you avoid the tooling cost of a forging.
Surface finish on the bearing seats is not cosmetic. A seat turned at Ra 1.6–3.2 μm can let the outer race creep under vibration. We usually specify Ra 0.8–1.6 μm for bearing seats and Ra 0.2–0.8 μm where a seal runs. That finish is achievable on a lathe with a wiper insert, and it is cheap compared to a field failure.
Step by step: size a gearbox from scratch
Follow the order. Changing the order hides errors.
- 1Step 1 – Collect motor and load dataWrite down motor power in kW, motor rated speed in rpm, motor rated torque, peak torque ratio, driven mass, friction coefficient and required output speed. If the output speed is known, the ratio is input rpm divided by output rpm. Round the ratio to the nearest available catalog value, for example 1,450 / 60 = 24.2, so choose 25:1.
- 2Step 2 – Compute input torqueUse T (N·m) = 9550 × P (kW) / n (rpm). For 2.2 kW at 1,450 rpm, T = 9550 × 2.2 / 1450 = 14.5 N·m. Keep one decimal. If your motor data sheet already lists rated torque, use it and skip this step, but verify with the formula because data sheets sometimes list stall torque instead.
- 3Step 3 – Multiply by ratio and efficiencyT_out = T_in × i × η. With 14.5 N·m, ratio 25 and efficiency 0.95, T_out = 344 N·m. Note that this is the available torque, not the required torque. Required torque comes from the load, and the two numbers should be compared, not assumed equal.
- 4Step 4 – Add friction and acceleration torqueAdd 10 to 30 percent for bearing and seal drag on a screw axis. Add T_acc = J × α where α = (2π × Δn) / (60 × t) and t is the acceleration time in seconds. A 0.002 kg·m² load accelerating to 60 rpm in 0.2 s needs α = 31.4 rad/s² and T_acc = 0.063 N·m at the output. Small numbers at the output become large numbers at the motor once divided by the ratio.
- 5Step 5 – Apply the service factorMultiply the required running torque by the service factor from the table above. A 344 N·m load with a moderate shock factor of 1.5 needs a gearbox rated at 516 N·m or more. Never apply the factor to the catalog rating; apply it to the demand. This is the single most common sizing mistake in our review work.
- 6Step 6 – Check peak, thermal and radial loadConfirm that the peak torque, including start and stop, stays below the catalog peak rating. Check thermal capacity in kW against the actual dissipated power, especially in a worm unit that runs continuously. Finally, check the radial and axial load on the output shaft. A chain sprocket mounted far out on the shaft can overload the bearing even when the torque is fine.
- 7Step 7 – Document units and marginRecord every value with its unit and the margin you used. A 15 to 25 percent margin above the serviced torque is normal for a clean, well-known load. Add more when the load data is estimated. On the drawing, state torque in N·m and note the service factor, so the next engineer does not have to reconstruct your assumptions.
Service factor by load type
Multiply the calculated running torque by this factor before you pick a model.
| Load type | Service factor | Typical duty |
|---|---|---|
| Uniform, steady | 1.0 – 1.3 | Fans, centrifugal pumps, light conveyors |
| Moderate shock | 1.3 – 1.5 | Mixers, rotary kilns, medium conveyors |
| Heavy shock | 1.5 – 2.0 | Crushers, punch presses, bucket elevators |
| Reversing with impact | 2.0 – 2.5 | Hoists, cranes, indexing tables |
| High inertia start | 2.5 – 3.0 | Large flywheels, mill drives |
Gearbox type versus typical efficiency
Use these ranges when you do not have a manufacturer curve.
| Type | Efficiency per stage | Best for |
|---|---|---|
| Helical, single stage | 0.96 – 0.98 | General reduction, low noise |
| Planetary, per stage | 0.94 – 0.97 | High ratio in a short body |
| Worm gear | 0.50 – 0.85 | High ratio, self-locking |
| Bevel helical | 0.94 – 0.97 | Right-angle drive, heavy duty |
| Cycloidal | 0.80 – 0.90 | Shock load, high ratio |
Size the demand, then pick the model
Calculate the required torque at the output, add friction and acceleration, multiply by the service factor, and only then open the catalog. If the margin is under 15 percent on a shock load, go one frame size up.
Questions engineers ask about gearbox torque
Can I calculate the gearbox torque from the motor nameplate alone?
Yes, for a first pass. Take the rated power in kW and the rated speed in rpm and apply T = 9550 × P / n. That gives shaft torque at rated load.
It does not tell you the peak torque, the starting torque or the thermal limit. Use the nameplate to bound the problem, then go back to the load data for the real sizing number.
Why is my calculated output torque higher than the load needs?
Because you calculated the available torque from the motor, not the required torque from the load. Available torque is what the drive can deliver. Required torque is what the machine consumes.
Compare the two. If available is far above required, you are carrying extra inertia and paying for acceleration you do not need. If available is below required after the service factor, the axis will stall on the first hard start.
How much margin should I leave on a gearbox selection?
For a well-known steady load, 15 to 25 percent above the serviced running torque is normal. For a shock load or an estimated load, use the service factor table and add 25 to 40 percent.
Margin is cheap in a gearbox and expensive in downtime. One frame size up usually costs far less than a replacement gearbox and a stopped line.
Does the gear ratio change the torque direction?
No. A reducer multiplies torque in the same rotational direction as the input, unless the design is a reversing gear set. A worm gear reverses direction depending on the lead hand, and a bevel pair can be set left or right hand.
What the ratio changes is magnitude and speed, not sense. Check the drawing for shaft arrangement before you design the mounting.
How do I convert lb·in or kgf·m into N·m?
Multiply lb·in by 0.113 to get N·m. Multiply kgf·m by 9.807 to get N·m. Multiply lb·ft by 1.356 to get N·m.
Do the conversion at the start, not the end. Mixed units are the most common reason a correct formula produces a wrong answer.
When is a machined prototype gearbox housing worth it?
When the volume is low, the geometry is still changing, or you need the unit running before a casting pattern is ready. A machined 6061-T6 or 7075 housing holds bore position to ±0.005 mm and can be revised in days.
Once the design freezes and the annual volume justifies tooling, move to casting or die casting. Until then, machining keeps the schedule and the geometry under your control.
Send us your gearbox drawing and load data
We machine reducer housings, output shafts, bearing seats and gear blanks, from one prototype to 10,000+ part runs. Quotation and a free DFM analysis come back within 12 hours.
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