Watts of Power a VF2 CNC Machine Draws: A Shop Guide
A VF2 sits near 6–10 kW during steady cutting, with short peaks toward 15 kW on heavy spindle loads. This guide shows engineers and shop planners how to read nameplate data, measure real current, and size a feed that will not trip under load.

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Key takeaways
What the VF2 Nameplate Really Tells You
The nameplate on a VF2 lists a total connected load, not a running draw. That figure assumes every motor starts at once, the spindle is at full rated output, the coolant pump is running, and the tool changer is mid-cycle. In practice you will never see that number on a clamp meter for more than a fraction of a second.
For a typical 40-taper VMC in this class, the spindle motor is the largest single load. A 15 kW (20 hp) spindle at continuous duty draws real watts only in proportion to the depth of cut and material removal rate. Cutting 6061 aluminum with a 12 mm end mill at moderate feed uses a small fraction of that rating. Hogging 4140 steel with a 50 mm face mill uses most of it.
So when someone asks about the watts of power a VF2 CNC machine uses, the honest answer is a range tied to the cut, not a single figure. Treat the nameplate as an upper bound and measure the real load before you commit to a breaker size.
- 1NameplateWorst-case connected load with every motor engaged.
- 2Measured cutWhat a clamp meter shows during a real toolpath.
- 3IdleControl, servos and lube hold a small steady load.
Watts of Power VF2 CNC Machine Draws in Each State
Break the machine into states and the numbers become manageable. With the control on, servos energized and spindle stopped, expect roughly 0.5–1.5 kW. Add the coolant pump and chip conveyor and you are near 1.5–2.5 kW. This is the load the machine carries between cuts, and it is what most shops underestimate when planning a panel.
During steady cutting the spindle load follows material and toolpath. Aluminum at moderate removal rates holds the spindle near 30–50% of rated power. Steel and stainless steel push higher, and titanium or Inconel can hold the spindle near 80% of rating for minutes at a time. Add axis servos, coolant and the tool changer and the total climbs into the 6–10 kW band for a 15 kW spindle machine.
Peaks come from acceleration. Spindle ramp from 0 to 10,000 rpm, a rapid traverse on all three axes at once, or a heavy interrupted cut can spike demand toward 15 kW for a few seconds. The breaker and feeder have to survive those peaks without tripping, even though the average is far lower.
- 1Idle0.5–1.5 kW with the spindle stopped.
- 2Coolant and conveyorAdds roughly 1–1.5 kW when running.
- 3Steady cut6–10 kW on a 15 kW spindle machine.
- 4PeakUp to about 15 kW during accel or heavy cuts.
Turning Watts Into Amps for Your Panel
Your electrician works in amps, not watts. For a three-phase feed the relation is watts equals volts times amps times the square root of three, times power factor. At 240 V three-phase with a power factor near 0.85, a 10 kW draw works out to roughly 28 A. At 15 kW it is near 42 A. That is why the VF2 is usually fed from a 50 A or 60 A three-phase breaker.
Voltage sags change the picture. A shop at the end of a long feeder sees the spindle pull more current for the same watts, and the drive trips on undervoltage before the breaker ever opens. Measure line voltage under load, not at rest. If it drops more than about 5% during a cut, the feeder is too small or the transformer is loaded by other machines.
Single-phase operation is not an option on a machine of this class. The spindle drive needs three-phase input to deliver rated torque. If your building only has single-phase service, plan for a rotary phase converter sized well above the machine rating, and expect some loss of spindle performance.
- 110 kW at 240 V 3-phaseAbout 28 A with power factor near 0.85.
- 215 kW at 240 V 3-phaseAbout 42 A, so a 50–60 A breaker.
- 3Voltage drop under loadKeep it under about 5% during a cut.
Duty Cycle and What the Watts Actually Cost
A machine that draws 8 kW during a cut does not draw 8 kW all day. Real duty cycle on a job shop VF2 is often 30–60% spindle-on time, with rapid moves, tool changes and part loading filling the rest. Multiply average load by hours to get kilowatt-hours, then by your local rate. For a shop running two shifts, that is the number that shows up on the utility bill.
Air cutting costs money too. Long rapids, conservative feeds and slow spindle ramp times all add idle watts without removing metal. If you are trying to justify a feed upgrade or a second machine, log the actual spindle-on percentage for a week. Most shops find it lower than they assumed, which changes the electrical plan.
Heat is the other cost. Every watt not turned into chip removal becomes heat in the spindle, drive or cabinet. A machine pushed near its rated watts for hours needs clean cabinet filters, working fans and a shop that can hold a reasonable ambient temperature. Overheating shortens drive life more than any other single factor.
- 1Spindle-on timeTypically 30–60% on a job shop machine.
- 2Energy costAverage kW times hours times your rate.
- 3HeatWaste watts load the cabinet and spindle bearings.
When the VF2 Power Envelope Is Too Small
A VF2 covers a lot of work, but its power ceiling is real. If your parts need deep pockets in hardened tool steel, or long roughing passes in Inconel, the spindle will spend most of its time near rating. That shortens tool life, forces light depths of cut, and pushes the machine into thermal drift that shows up as tolerance problems.
For that class of work, more spindle power and a stiffer structure matter more than a bigger table. Machines with higher-rated spindles and box ways hold tolerance through heavy cuts. If your typical part is a large aluminum plate, the VF2 envelope may also be too small before power ever becomes the limit.
The practical test is simple. Look at your worst-case part, not your average part. If the worst case holds the spindle above about 80% of rating for more than a few minutes, the machine is undersized for that job and the watts question turns into a capability question.
- 1Heavy steel roughingSpindle runs near rating for long stretches.
- 2High-temp alloysInconel and titanium need more spindle power and rigidity.
- 3Large platesTravel limits may bind before power does.
Step by Step: Measure the Real Draw Before You Install
Do these in order. Each step takes minutes and prevents a costly feeder mistake.
- 1Collect nameplate and manual dataWrite down spindle rating, total connected load, voltage and phase from the nameplate. Note whether the spindle is 15 kW or a different rating, because that sets the ceiling for every later number.
- 2Clamp the feed during a representative cutPut a true-RMS clamp meter on one phase of the feeder. Run a toolpath that matches your typical part, not a light finishing pass. Record amps during the heaviest 30 seconds of the cut.
- 3Convert amps to wattsUse watts equals volts times amps times 1.732 times power factor. Take the measured line voltage under load, not at rest. A power factor near 0.85 is a reasonable starting point for this class of machine.
- 4Log idle, cut and peak separatelyWrite down three numbers: idle kW, steady-cut kW and peak kW. Peak is the one that sizes the breaker, and it often shows up during spindle ramp rather than in the cut itself.
- 5Add coolant, conveyor and any optionsCoolant pumps, chip conveyors, hydraulic units and rotary tables add load. Include every option you plan to run at the same time as the spindle.
- 6Size the breaker and feeder for peakPick a breaker above the measured peak with margin for voltage sag and inrush. A 50–60 A three-phase breaker is typical for this machine class at 240 V.
- 7Verify voltage under load after installRe-measure line voltage while the spindle is cutting. If it drops more than about 5%, fix the feeder before you blame the machine for drive faults.
VF2 Load Cases at a Glance
Approximate values for a 15 kW spindle machine at 240 V three-phase, power factor near 0.85.
| Operating state | Approx. watts | Approx. amps | Notes |
|---|---|---|---|
| Control on, spindle stopped | 0.5–1.5 kW | 2–4 A | Servos and lube hold steady load |
| Coolant and conveyor running | 1.5–2.5 kW | 4–7 A | Adds load between cuts |
| Aluminum, moderate cut | 4–8 kW | 12–23 A | Spindle at 30–50% of rating |
| Steel, heavy cut | 8–12 kW | 23–34 A | Spindle near 60–80% of rating |
| Spindle ramp or rapid peak | Up to about 15 kW | Up to about 42 A | Seconds only, sizes the breaker |
Measure first, then commit to a feed size
Nameplate watts tell you the ceiling. A clamp meter on your worst-case part tells you what you actually need. Do that before you buy the breaker.
Frequently asked questions
Can a VF2 run on 220 V single-phase?
No. The spindle drive needs three-phase input to deliver rated torque, and the machine is built for a three-phase feed. Single-phase service requires a phase converter sized well above the machine rating, and spindle performance will not match a true three-phase supply.
Is the nameplate wattage the same as running watts?
No. The nameplate lists the worst-case connected load with every motor engaged. Real running watts depend on material, toolpath, depth of cut and spindle load, and are usually well below the nameplate figure.
How long can a VF2 hold peak power?
Peaks come from acceleration, not steady cutting, so they last seconds at a time. Sustained operation near the top of the spindle rating for minutes will raise temperatures and shorten component life, so plan your roughing passes to sit well below the ceiling.
Does spindle speed change the watts drawn?
Yes, but not in the way most people assume. Higher rpm increases no-load friction and windage, while cutting load depends mainly on material removal rate. A fast light pass can draw less than a slow heavy pass in the same material.
How do I know if my shop feeder is too small?
Measure line voltage while the spindle is cutting. A drop of more than about 5% from the at-rest value means the feeder or transformer is loaded too heavily. Drive undervoltage faults during heavy cuts usually point to the same cause.
Should I size the breaker for average or peak current?
Size for peak. The breaker has to survive spindle ramp, rapid moves and inrush without nuisance trips, even though the average draw is much lower. A 50–60 A three-phase breaker is typical for this machine class at 240 V.
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